<PRE><B>Question 36833</B>
Let the number be x
and the square of the number be x^2


x- x^2 = 2/9
Multiply by 9 on both sides
9x- 9x^2 = 2
9x- 9x^2 - 2 = 0
-9x^2 +9x -2 = 0
Multiply by a -1 on both sides
9x^2 -9x +2 = 0
9x^2 -6x - 3x +2 = 0
3x(3x-2) -1(3x - 2) = 0
(3x -1 )(3x - 2) = 0

X = 1/3, 2/3



Verify the results

x  - x^2 
1/3 - (1/3)^2
1/3 - 1/9

3-1
----
9

= 2/9


x  - x^2 
2/3 - (2/3)^2
2/3 - 4/9

6-4
----
9

= 2/9</PRE>