Question 316197
{{{ 4 sqrt (x) = 8 + 2 sqrt (x) }}}
Let {{{u=sqrt(x)}}}
, then
{{{ 4u=8+2u}}}
{{{ 2u=8}}}
{{{ u=8}}}
{{{ sqrt(x)=8}}}
{{{ x=64}}}
None of the above.
b) is the closest answer.