Question 316117
<font face="Garamond" size="+2">


Use the sum of two cubes factorization:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(a^3\ +\ b^3\right)\ =\ (a\ +\ b)\left(a^2\  -\ 2ab\ +\ b^2\right)]


You get the real factor directly and the two complex roots come from using the quadratic formula.


Hint: *[tex \LARGE 216\ =\ 6^3] 



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>