Question 316105
{{{log(2,(8)) + log(2,(16)) = log(2,(8*16)) = log(2,(128)) = log(2,(2^7)) = 7*log(2,(2)) = 7*1 = 7}}}



So {{{log(2,(8)) + log(2,(16)) = 7}}}



Or alternatively...


{{{log(2,(8)) + log(2,(16)) = log(2,(2^3)) + log(2,(2^4)) = 3*log(2,(2)) + 4*log(2,(2)) = 3*1 + 4*1 = 3+4 = 7}}} giving the same answer.