Question 316077
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One question per post.  I'll do the first one for you and you can re-post the other two individually.


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ \log_b(u)\ =\ 0\ \ \Leftrightarrow\ \ u\ =\ 1]


Therefore:


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ \log(6x\ +\ 5)\ =\ 0\ \ \Leftrightarrow\ \ 6x\ +\ 5\ =\ 1\ \Rightarrow\ \ x\ =\ 1]



John
*[tex \Large e^{i\pi}\ +\ 1\ =\ 0]
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