Question 316062


{{{5x+2y=-3}}} Start with the given equation.



{{{2y=-3-5x}}} Subtract {{{5x}}} from both sides.



{{{2y=-5x-3}}} Rearrange the terms.



{{{y=(-5x-3)/(2)}}} Divide both sides by {{{2}}} to isolate y.



{{{y=((-5)/(2))x+(-3)/(2)}}} Break up the fraction.



{{{y=-(5/2)x-3/2}}} Reduce.



So the equation {{{y=-(5/2)x-3/2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-5/2}}} and the y-intercept is {{{b=-3/2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{3}{2}\right)]