Question 654
This one can't be factored. Use the quadratic formula.
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
 
Where the equation is in the form {{{ax^2 + bx + c = 0}}}
 
So, a = 6, b = 7, and c = -25.
 
{{{y = (-7 +- sqrt( 7^2-4*6*(-25) ))/(2*6) }}}
 
Simplify what is under the square root and the denominator.
{{{y = (-7 +- sqrt( 49 + 600 ))/12 }}}
 
This leaves you with:
{{{y = (-7 +- sqrt( 649 ))/12 }}}
 
This also leaves you with a situation where you have to decide if you need to get a decimal answer or if it is okay to leave it in the radical form.