Question 315792
If b is inversely proportional to the square of c
b = {{{1/c^2}}}
let k = constant of variation
b = {{{k/c^2}}}
:
 b is 5/9 when c is 3, find k
{{{5/9}}} = {{{k/3^2}}}
{{{5/9}}} = {{{k/9}}}
cross multiply
9k = 5*9
9k = 45
k = {{{45/9}}}
k = 5
:
b = {{{5/c^2}}} is the equation
:
find b when c is 5.
b = {{{5/5^2}}}
b = 5/25
b = {{{1/5}}}