Question 315732
Since {{{log(a,(x))=log(10,(x))/log(10,(a))}}}, this means that the restrictions on 'a' are very similar to the restrictions on 'x'. However, we must make sure that {{{log(10,(a))<>0}}}. So this means that {{{a<>1}}}



For 'x', we can plug in any positive number (since we cannot take the log of 0 or any negative number). So this means that {{{x>0}}}. Because the conditions on 'a' are similar, this means that {{{a>0}}} as well but we must add that {{{a<>1}}}


Let me know if this makes sense to you.