<PRE><B>Question 315627</B>
A long distance trucker traveled 180 miles in one direction during a snow storm.
 The return trip in rainy weather was accomplished at double the speed and took 5 hours less time.
 Find the speed going.
:
Let s = the speed going
then
2s = return speed
:
Write a time equation: time = dist/speed
:
go time - return time = 5 hrs
{{{180/s}}} - {{{180/(2s)}}} = 5
multiply by 2s, results:
2(180) - 180 = 2s(5)
360 - 180 = 10s
180 = 10s
s = {{{180/10}}}
s = 18 mph going
:
:
check solution by finding the actual times
180/18 = 10 hrs
180/36 =  5 hrs
---------------
differ = 5 hrs</PRE>