Question 315748
{{{(2x+1)/(x+2) + (4x+11)/(x+2)}}}
<pre><b>
Since they have the same denominator just put the sum of
the numerators over the common denominator

{{{((2x+1)+ (4x+11))/(x+2)}}}

Remove the parentheses:

{{{(2x+1+ 4x+11)/(x+2)}}}

{{{(6x+12)/(x+2)}}}

Factor 6 out of the numerator:

{{{(6(x+2))/(x+2)}}}

Cancel the {{{(x+2)}}}'s

{{{(6(cross(x+2)))/(cross(x+2))}}}

The answer is just 

6

Edwin</pre>