Question 315427
We're going to use the following identities:


1) {{{log(b,(x^y))=y*log(b,(x))}}}


2) {{{log(b,(A*B))=log(b,(A))+log(b,(B))}}}




So first using identity #2 and then identity #1, we get:



{{{log(b,(x^(1/2)^""y^3))=log(b,(x^(1/2)))^""+log(b,(y^3))=(1/2)log(b,(x))+3*log(b,(y))}}}



So in short, {{{log(b,(x^(1/2)^""y^3))=(1/2)log(b,(x))+3*log(b,(y))}}}