Question 315420
log(base b)x + log(base b)(x+2)- log(base b)8
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Applicable Rules:
log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
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= logb[x*(x+2)/8]
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= logb[(x^2+2x)/8]
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Cheers,
Stan H.