Question 315365
let the first integer be x
second = x+2
third = x+4
..
(x+2)(x+4)=10x+20
x^2+6x+8=10x+20
x^2-4x-12=0
x^2-6x+4x-12=0
x(x-6)+4(x-3)=0
(x-6)(x+4)=0
x= 6
the numbers are 6,8,10.