Question 315258
h(t) = -(1/2)32t^2 + Vt + Ho
where
h(t) is height 
t is time
V is initial velocity (0)
Ho is initial height (144)
.
0 = -(1/2)32t^2 + 0t + 144
0 = -16t^2 + 144
-144 = -16t^2
9 = t^2
3 sec = t