Question 315194
I have another question I am stuck on. Evaluate the logarithmic equation for three values of x that are greater than -1, three values of x that are between 0 and-1, and at x = -1. Show your work. Use the resulting ordered pairs to plot the graph. State the equation of the line asymptotic to the graph. 
y=log2(x+2)
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I think you mean log base 2 ?
{{{y = log(2,(x+2))}}}
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Calculators don't have logs base 2, so you use the base change formula
{{{log(2,(x+2)) = log(x+2)/log(2)}}}
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You sub the values for x, and find y.
It says 3 values > -1 and 3 values between -1 and 0.  The values between -1 and 0 will be greater than -1 ???  That's redundant.
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x	y
-1	0
-0.8	0.263034406
-0.6	0.485426827
-0.4	0.678071905
-0.2	0.847996907
0	1
0.2	1.137503524
0.4	1.263034406
0.6	1.378511623
0.8	1.485426827
1	1.584962501
I used Excel

email me at moral loophole@aol.com if you want a graph