Question 315142
E) is the correct answer.
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I. when {{{n<0}}}, {{{n^2>n}}} always.
{{{n^2>n}}}
Divide by {{{n}}} and change the sign of the inequality
{{{highlight(n<1)}}}
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II. when {{{n<0}}}, {{{2n<n}}} always.
{{{2n<n}}}
Divide by {{{n}}} and change the sign of the inequality
{{{highlight(2>1)}}}
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III. when {{{n<0}}}, {{{n^2<-n}}}   holds when {{{-1<n<0}}}
{{{n^2<-n}}}
Divide by {{{n}}} and change the sign of the inequality
{{{highlight(n>-1)}}}