Question 315106
{{{((9a^(-3)b^3c^6)/(-3a^(-5)b^(-2)c))^2=((9/-3)*a^(-3-(-5))*b^(3-(-2))*c^(6-1))^2}}}
{{{((9a^(-3)b^3c^6)/(-3a^(-5)b^(-2)c))^2=((-3)*a^(2)*b^(5)*c^(5))^2}}}
{{{((9a^(-3)b^3c^6)/(-3a^(-5)b^(-2)c))^2=(-3)^2*a^(4)*b^(10)*c^(10)}}}
{{{((9a^(-3)b^3c^6)/(-3a^(-5)b^(-2)c))^2=9a^(4)b^(10)c^(10)}}}