Question 315048
I think I have the numerator figured out. 
{{{(2x^2+4x-30)=2(x^2+2x-15)=2(x+5)(x-3)}}}
Could you re-post your equation because I can't figure the denominator. 
{{{x^2-25x-3}}} does not have integer factors. 
Is it possibly, {{{x^2-2x-3=(x-3)(x+1)}}}
Then the solution would be,
{{{(2x^2+4x-30)/(x^2-2x-3)=(2(x+5)(x-3))/((x-3)(x+1))}}}
{{{(2x^2+4x-30)/(x^2-2x-3)=(2(x+5)cross((x-3)))/(cross((x-3))(x+1))}}}
{{{(2x^2+4x-30)/(x^2-2x-3)=(2(x+5))/(x+1)}}}
If you need to re-post, use x^2 for {{{x^2}}}.