Question 315092
{{{drawing(300,300,-5,10,-5,5,locate(-4.7,1,A),grid(1),line(2,10,2,-10),circle(-4,1,.2),graph(300,300,-5,10,-5,5,0))}}}
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I'm not sure what you mean by "over top of AB".
For the line {{{x=2}}} to bisect AB, the x distance from A to {{{x=2}}} must be the same as the distance from B to {{{x=2}}} and A and B must have the same y-coordinate.
{{{DELTA*x=2-(-4)=6}}}
{{{Bx=2+6=8}}}
{{{By=1}}}
Therefore point B must be ({{{8}}},{{{1}}}).
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{{{drawing(300,300,-5,10,-5,5,locate(-4.7,1,A),locate(8.5,1,B),grid(1),line(2,10,2,-10),circle(8,1,.2),blue(line(-4,1,8,1)),circle(-4,1,.2),graph(300,300,-5,10,-5,5,0))}}}