<PRE><B>Question 315037</B>
at noon a private plane left Austin for Los Angeles, 2300km away, flying at 500km/h. 
one hour later a jet left Los Angeles for Austin at 700km/h. 
at what time did they pass each other?
:
Let t = travel time of the private plane
then
(t-1) = travel time of the jet
:
When the aircraft meet, the sum of their distances will be 2300 km
Write a dist equation; dist = speed * time
:
jet dist + private dist = 2300 km
700(t-1) + 500t = 2300
:
700t - 700 + 500t = 2300
:
1200t = 2300 + 700
:
1200t = 3000
t = {{{3000/1200}}}
t = 2.5 hrs
:
12:00 + 2:30 = 2:30 PM the planes will meet
:
:
Confirm solution by finding the distance
2.5(500) = 1250
1.5(700) = 1050
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total dist 2300</PRE>