Question 315051
find all points having an x coordinate of 9, whose distance from the point (3,-2) is 10
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Find the circle of radius 10 with its center at (3,-2)
That's (x-3)^2 + (y+2)^2 = 100
Sub 9 for x
6^2 + (y^2 + 4y + 4) = 100
y^2 + 4y + 4 = 64
y^2 + 4y - 60 = 0
Solve for y
y = (-4/2) ± sqrt(16 + 240)/2
y = -2 ± 8
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--> (9,6) and (9,-10)
Don't make it a thesis.