Question 314952
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Your expression makes no sense.  You can't "solve" anything unless there is an equals sign somewhere, and you can't even evaluate a logarithm unless there is an argument.  And you don't specify if the -1 exponent is on the overall function (meaning you are looking for the inverse function) or whether it is on the argument (meaning you are taking the reciprocal).


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -\log_{3.5}^{-1}(?)\ =\ ?]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -\log_{3.5}(?)^{-1}\ =\ ?]






John
*[tex \LARGE e^{i\pi} + 1 = 0]
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