Question 314962
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Since the area of a circle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \pi r^2]


The radius in terms of the area must be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \sqrt{\frac{A}{\pi}}]


The circumference, once the radius is known is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ C\ =\ 2\pi r]


Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ C\ =\ 2\pi\sqrt{\frac{A}{\pi}}]


Which can be simplified to


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ C\ =\ 2\sqrt{\pi A}]


Plug in your value for the area and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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