<PRE><B>Question 314832</B>
I assume you mean the car is traveling at 72 kph.
Convert from kph to m/s.
72 km/hr*(1 hr/3600 sec)*(1000m/km)=20 m/sec
{{{a=(vf-vi)/t=(20-0)/10=2}}} m/sec^2
The average acceleration is 2 m/s^2.
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The average velocity is 
{{{Vave=(Vf+Vi)/2=(20+0)/2=10}}} m/s
The average velocity is 10 m/s.
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The distance traveled, at constant acceleration, is,
{{{d=(1/2)at^2=(1/2)(2)(10)^2=100 m}}}
The car traveled 100 m </PRE>