Question 314898
1.{{{8x-4y=-64}}}
2.{{{3x+26=y}}}
Substitute eq. 2 directly into eq. 1,
{{{8x-4(3x+26)=-64}}}
{{{8x-12x-104=-64}}}
{{{-4x=40}}}
{{{x=-10}}}
Then from eq. 2,
{{{y=3(-10)+26}}}
{{{y=-30+26}}}
{{{y=-4}}}
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{{{ drawing( 300,300, -12, 3, -12, 3,grid(1),circle(-10,-4,.3), graph( 300,300, -12, 3, -12, 3, 3x+26, (8x+64)/4)) }}}