Question 314794
put into logarithmic form. 4^x+1=8
.
I'm assuming you meant:
4^(x+1)=8
.
So, starting with:
{{{ 4^(x+1)=8 }}}
{{{ log(4,4^(x+1)) = log(4,8) }}}
{{{ (x+1) = log(4,8) }}}
{{{ (x+1) = log(8)/log(4) }}}
{{{ x = log(8)/log(4) - 1 }}}