Question 314842
The slope-intercept form of a line is {{{y=mx+b}}} so you know the slope, {{{m}}}, and the y-intercept, {{{b}}}.
Plot the intercept (0,b).
The slope gives the change in y, divided by the change in x. 
Here's how to handle it if the slope is a fraction, the slope is an integer, or the slope is in decimal form.
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If the slope is a fraction, take the denominator as a step in x.
Example:
{{{y=(4/5)x+3}}}
You are starting at (0,3) and the slope is (4/5).
Move 5 places in x. 
You will then move the numerator as the step in y.
Move 4 places in y.
(0,3)+(5,4)=(5,7)
Now you have two points and can plot the line.
{{{drawing(300,300,-5,10,-5,10,grid(1),circle(0,3,.3),circle(5,7,.3),graph(300,300,-5,10,-5,10,(4/5)x+3))}}}
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If the slope is an integer, take 1 step in x. 
Then take the slope as the step in y.
(0,b)+(1,m)=(1,m+b)
Now you have two points and can plot the line.
Example:
{{{y=3x+5}}}
(0,5)+(1,3)=(1,8)
{{{drawing(300,300,-5,5,-5,10,grid(1),circle(0,5,.2),circle(1,8,.2),graph(300,300,-5,5,-5,10,3x+5))}}}
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If the slope is a decimal, follow the previous instructions.
(0,b)+(1,m)=(1,m+b)
Now you have two points and can plot the line.
Example:
{{{y=-1.35x+2}}}
(0,2)+(1,-1.35)=(1,0.65)
{{{drawing(300,300,-5,5,-5,5,grid(1),circle(0,2,.2),circle(1,0.65,.2),graph(300,300,-5,5,-5,5,-1.35x+2))}}}
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