Question 314760
I think this is what you mean,
1.{{{x+4y=-1}}}
2.{{{3x+y=8}}}
From eq. 1,
{{{x=-4y-1}}}
{{{3x=-12y-3}}}
Substitute into eq. 2,
{{{(-12y-3)+y=8}}}
{{{-11y=11}}}
{{{highlight( y=-1)}}}
Then from above,
{{{x=-4y-1}}}
{{{x=-4(-1)-1}}}
{{{x=4-1}}}
{{{highlight( x=3)}}}