Question 314862
Only the first two are equations so only those can be solved.
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{{{30/(1+6e^(-5x))=10 }}}
{{{30=10(1+6e^(-5x))}}} 
{{{1+6e^(-5x)=3}}}
{{{6e^(-5x)=2}}} 
{{{e^(-5x)=2/6=1/3}}}
{{{-5x=ln(1/3)}}}
{{{highlight(x=-ln(1/3)/5)}}}
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 {{{ln(x^2+3x)-ln(10)=0 }}}
 {{{ln(x^2+3x)=ln(10)}}}
{{{x^2+3x=10}}}
 {{{x^2+3x-10=0}}}
{{{(x+5)(x-2)=0}}}
Two solutions:
{{{x+5=0}}}
{{{highlight( x=-5)}}}
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{{{x-2=0}}}
{{{highlight( x=2)}}}
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Please re-post the other two if you still need help with them.