Question 314784
{{{3x=4y+5}}}
{{{4y=3x-5}}}
{{{y= (3/4)x-5/4}}}
Perpendicular lines have slopes that are negative reciprocals.
{{{m1*m2=-1}}}
{{{(3/4)*m2=-1}}}
{{{m2=-4/3}}}
Use the point-slope form of a line,
{{{ y-yp=m(x-xp)}}}
{{{y-(-3)=-(4/3)(x-2)}}}
{{{highlight_green( y+3=-(4/3)(x-2))}}}
Convert to slope-intercept form, {{{y=mx+b}}}
{{{y+3=-(4/3)x+8/3}}}
{{{y=-(4/3)x+8/3-9/3}}}}
{{{highlight_green( y= -(4/3)x-1/3 )}}}
{{{ drawing( 300, 300, -5, 5, -5, 5,grid(1),circle(2,-3,.2),graph( 300, 300, -5, 5, -5, 5, -(4/3)x-1/3, (3/4)x-5/4)
) }}}