Question 314750
hey,

Well the initial equation would be:

S(size)n=100(1.08^n)

So for the first year:

S1= 100(1.08^1)= 108 people
S2= 100(1.08^2)= 116.64 => so 117 people roughly
S3= 100(1.08^3)= 125.97 => so 126 people roughly

As shown above the size at n years is :

100(1.08^n)

As for the algebraic equation:

we would use the one above:

200 = 100(1.08^n)
and you would use log

I hope this helps!