Question 314713
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What is "confuised" and what does the condition of being whatever that is have to do with determining the measurement of a square?


Let *[tex \Large x] represent the measure of the side of the original square.  Then *[tex \Large x\ +\ 3] is the measure of the side of the enlarged square.


The area of a square is given by squaring the measure of one side.  Hence, *[tex \Large (x\ +\ 3)^2] is a representation of the area of the enlarged square.  Also, we are given that *[tex \Large 169\text{ ft^2}] is a representation of the area of the enlarged square.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ 3)^2\ =\ 169]


Taking the square root of both sides and discarding the negative root because we  are seeking a positive measure of length:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 3\ =\ 13]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 10]


And since we set up the problem so that *[tex \Large x] represents the measure of the side of the original square, that is the answer.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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