Question 314693
Let x, x+2 & x+4 be the 3 integers.
(x+2)^2+x=(x+4)^2-75
x^2+4x+4+x=x^2+8x+16-75
x^2-x^2+5x-8x=-4+16-75
-3x=-63
x=-63/-3
x=21 ans.
Proof:
(21+2)^2+21=(21+4)^2-75
23^2+21=25^2-75
529+21=625-75
550=550