Question 314659
Diameter={{{D=4-(-4)=8}}}
{{{R=D/2=4}}}
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The center is the midpoint of the given points.
{{{xm=(3+3)/2=3}}}
{{{ym=(4-4)/2=0}}}
(3,0)
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The general equation for a circle centered at (h,k) with a radius R is:
{{{(x-h)^2+(y-k)^2=R^2}}}

{{{(x-3)^2+(y-0)^2=4^2}}}
{{{highlight((x-3)^2+y^2=16)}}}