Question 314650
Hey,

Well for this question you need to find the hypotenuse of the triangle that the two coordinates make. 

You need to find the lengths of the two bases to find the length of the hypotenuse(distance) using the pythagorean theorem: a^2 + b^2 = c^2

So to find the vertical one, we use the y coordinates 7 and -4:

7-(-4) => 7+4=11

And then we use the x coordinates to find the horizontal one with -3 and 6:

6-(-3)=6+3=9 

So we plug these into the theorem:

9^2 + 11^2 = c^2    =>   81 + 121 = 202  => c^2 = 202 

Find the square root of both sides and  you get:14.21...Which is the distance

I hope this helps!

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