Question 314489
1.{{{A+B=20}}}
2.{{{3*A=2*B}}}
Multiply eq. 1 by 3,
{{{3A+3B=60}}}
Now substitute eq. 2,
{{{2B+3B=60}}}
{{{5B=60}}}
{{{highlight(B=12)}}}
Then from eq. 1,
{{{A+12=20}}}
{{{highlight(A=8)}}}