Question 314539
First, convert the equation {{{y=-log(3,x-1)}}} to the corresponding equation in "ln":

{{{y=-(ln(x-1))/(ln3)}}}


If x=2, then {{{y=-ln1/ln3=0}}}
If x=1.5, then {{{y=-ln.5/ln3=.63}}}
If x=1.8, then {{{t=-ln.8/ln3=.20}}}

{{{graph(300,300,-10,10,-10,10, -log(3,x-1) ) }}}


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus