Question 314550
Complete the square in x and y.
{{{x^2+y^2 + 6x + 4y + 12=0}}}
{{{(x^2+6x)+(y^2+4y) + 12=0}}}
{{{(x^2+6x+9)+(y^2+4y+4) + 12=9+4}}}
{{{(x+3)^2+(y+2)^2 =1}}}
Compare to the general equation for a circle centered at (h,k) with a radius R is:
{{{(x-h)^2+(y-k)^2=R^2}}}
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Center:({{{-3}}},{{{-2}}})
Radius:{{{R=1}}}