Question 4736
{{{f(x) = sqrt (x-10) }}} or
{{{ y = sqrt (x - 10) }}}


To find the inverse function, 
STEP 1:  interchange the x and y, and 
STEP 2:  solve for y.


STEP 1:  {{{x = sqrt (y -10) }}}


STEP 2:  Square both sides:
{{{x^2 = y- 10 }}}


Add 10 to each side:
{{{x^2 + 10 = y}}}


This {{{y = x^2 + 10 }}} is the inverse function 
So, {{{f^(-1) = x^2 + 10 }}}


R^2 at SCC