Question 314424
Hey, 

For this one you need to just write it all out

You know two things:

x+y=133

and

4x=3y

what you want to do is substitute these numbers for each other:

If you minus both sides by y in the first equation you'll get:

x=133-y

Then you can put this into the other equation:

4(133-y)=3y  =>   532-4y=3y =>   532=7y => y=532/7  => y=76

You can then put this back into the original equation:

x+76=133  => x=133-76  =>   x=57

I hope this helped!