<PRE><B>Question 314422</B>
8x^2 over x^2-9 multiplied by x^2 + 6x+9 over 16x^3 
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(8x^2)/(x^2-9) * (x^2+6x+9)/(16x^3)
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Factor to get:
[8x^2/[(x-3)(x+3)] * [(x+3)^2/(16x^3)]
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Cancel any factor common to a numerator and a denominiator,
such as 8,x^2,(x+3), to get:
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[1/(x-3)] * [(x+3)/x]
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Multiply to get:
= (x/3)/[x(x-3)]
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Cheers,
Stan H.</PRE>