Question 314366
{{{x/5=8/x}}}


{{{x^2=40}}}
{{{x=0+-sqrt(40)}}}
{{{x=0+-sqrt(4)*sqrt(10)}}}
{{{x=2sqrt(10)}}} or {{{x=-2sqrt(10)}}}


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus