Question 314189
First multiplier : {{{x^2}}}
{{{x^2*(x-2)=x^3-2x^2}}}
Subtract from the original polynomial to get the remainder,
{{{(x^3-3x^2-3)-(x^3-2x^2)=-x^2-3}}}
Next multiplier : {{{-x}}}
{{{-x(x-2)=-x^2+2x}}}
Subtract from the remainder to get the new remainder,
{{{(-x^2-3)-(-x^2+2x)=-2x-3}}}
Last multiplier:{{{-2}}}
{{{-2(x-2)=-2x+4}}}
Subtract from the remainder to get the new remainder,
{{{(-2x+4)-(-2x+4)=-7}}}
Put it all together with the final remainder,
 {{{(x^3-3x^2-3)/(x-2)=(x^2-x-2)-7/(x-2)}}}