Question 314161
{{{y^(8/3)=2.83010 }}}

{{{(y^((8/3))^(3/8))=2.83010^(3/8)}}}
{{{y^((8/3)*(3/8))=2.83010^(3/8)}}}
{{{y^(1)=y= 2.83010^(3/8)}}} or approximately
{{{y=1.4772}}}