Question 314009
solve the equation by a method of your choice. 
1. x^2 -2x -15=0
(x-5)(x+3) = 0
x = 5 or x = -3
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Write a quadratic equation that has the given solutions.
1. -2 and 5
y = (x+2)(x-5) 
y = x^2-3x-10
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2. -3 and -5
y = (x+3)(x+5)
y = x^2+8x+15
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Cheers,
Stan H.
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