Question 313962
4x^2=3x+2
4x^2-3x-2=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(3+-sqrt[-3^2-4*4*-2])/2*4
x=(3+-sqrt[9+36])/8
x=(3+-sqrt41)/68x=(3+-6.403)/6
x=(3+6.403)/8
x=9.403/8
x=1.175 ans.
x=(3-6.403)/8
x=-3.403/8
x=-.425 ans.