Question 313876
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{b}\ +\ 3\ =\ c]


Add -3 to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{b}\ =\ c\ -\ 3]


Multiply both sides by *[tex \LARGE b]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ b(c\ -\ 3)]


Multiply both sides by *[tex \LARGE \frac{1}{c\ -\ 3}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ =\ \frac{a}{c\ -\ 3}]


<i>That is unless you meant:</i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{b\ +\ 3}\ =\ c]


Multiply both sides by *[tex \LARGE b\ +\ 3]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ c(b\ +\ 3)]


Multiply both sides by *[tex \LARGE \frac{1}{c}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ +\ 3\ =\ \frac{a}{c}]


Add *[tex \LARGE -3] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ =\ \frac{a}{c}\ -\ 3]


Next time, please use parentheses to make your mathematical expressions clear -- that way I don't have to guess or do double work.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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