Question 313875
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If *[tex \LARGE \alpha] is a zero of a polynomial function in *[tex \LARGE x], then *[tex \LARGE x\ -\ \alpha] is a factor of the polynomial.


Your quadratic is therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ (-4))(x\ -\ 1)\ =\ (x\ +\ 4)(x\ -\ 1)\ =\ 0]


Use FOIL to expand the binomial to put it into *[tex \LARGE ax^2\ +\ bx\ +\ c\ =\ 0] form



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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