<PRE><B>Question 313737</B>
A company owns 400 laptops. Each laptop has an 8% probability of not working. You randomly select 20 laptops for your salespeople.
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Binomial Problem with n = 20 and p = 0.08
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A) What is the likelihood that 5 will be broken?
P(x = 5) = 20C5*0.08^5*0.92^15 = binompdf(20,0.08,5) = 0.0145
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B) What is the likelihood that they will all work?
Ans: 0.92^20 = 0.1887
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C) what is the likelihood that they will all be broken? 
Ans: 0.08^20 = 1.1529x10^-22
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Cheers,
Stan H.
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